SentenceTransformer(
(0): Transformer({'max_seq_length': 512, 'do_lower_case': False, 'architecture': 'BertModel'})
(1): Pooling({'word_embedding_dimension': 768, 'pooling_mode_cls_token': False, 'pooling_mode_mean_tokens': True, 'pooling_mode_max_tokens': False, 'pooling_mode_mean_sqrt_len_tokens': False, 'pooling_mode_weightedmean_tokens': False, 'pooling_mode_lasttoken': False, 'include_prompt': True})
(2): Normalize()
)pip install -U sentence-transformers1from sentence_transformers import SentenceTransformer
2
3# Download from the 🤗 Hub
4model = SentenceTransformer("ModelEvolution/zone")
5# Run inference
6queries = [
7 "Write a concise summary of the following. Be sure to preserve important details: The possibilities here are endless. Magic and technology are often what authors of genre fiction think of first when they think about worldbuilding, and they can be the most fun parts of worldbuilding. When you\u2019re thinking about magic and technology, you can bend rules liberally:",
8]
9documents = [
10 'Magic and technology are central and often the most enjoyable elements of worldbuilding in genre fiction, offering limitless creative possibilities. Authors can freely bend rules when developing these aspects.',
11 'Natsuki: (sniffling and grinning) “Look at her! She’s so tiny and cute… Sayori, you did amazing. I can’t believe we all just… delivered a baby together.”\n\nYuri: (clasping her hands, still trembling with adrenaline) “Yes… Sayori, you were incredibly brave. And Sachiko is beautiful. She’s so precious.”\n\nMonika: (letting out a deep breath, trying to steady her nerves) “I’m so proud of all of us. Sayori, you were so strong, and everyone worked together perfectly. I’m just… so relieved Sachiko is here, safe and healthy.”\n\nMC: (still kneeling at Sayori’s side, brushing Sayori’s hair back gently) “You’re so strong, Sayori. I love you… both of you.”\n\nSayori: (smiling through tears at her friends and husband, cradling Sachiko) “Thank you, everyone… I don’t know what I would have done without you. Sachiko already has the best family and friends in the world.”\n\n(Sachiko’s cries quiet as she nestles into Sayori’s arms.)\n\nMonika: (softly) “Just rest, Sayori. The paramedics should be here any second to check on you and the baby. Until then, we’ll all be right here.”\n\nNatsuki: (wiping her face with her sleeve) “If you ever need anything, Sayori, just say the word. I’ll bring you cupcakes every day, I promise!”\n\nYuri: (smiling warmly) “And I’ll read Sachiko as many stories as she’d like. Anything to help.”\n\nSayori: (laughs weakly) “She’s so lucky to have all of you. And so am I.”\n\n(The clubroom, once bustling with panic and activity, falls into a peaceful silence as everyone gathers around Sayori and baby Sachiko, overwhelmed by love and relief.)\n\nMC: (quietly) “Welcome to the world, Sachiko. You’re already so loved.”\n\n(The sound of approaching sirens echoes faintly outside, but for a moment, the Literature Club just sits together, basking in the miracle they helped deliver.)\n\n**END SCENE**',
12 '**Lista de 20 palabras holandesas:** \n1. Hond (perro) \n2. Bloemen (flores) \n3. Regen (lluvia) \n4. Fiets (bicicleta) \n5. Appel (manzana) \n6. Vuurwerk (fuegos artificiales) \n7. Kat (gato) \n8. Boom (árbol) \n9. Sneeuw (nieve) \n10. Zon (sol) \n11. Muziek (música) \n12. Dansen (baile) \n13. Boek (libro) \n14. Vis (pescado) \n15. Wind (viento) \n16. Maan (luna) \n17. Boot (bote) \n18. Lachen (reírse) \n19. Schaatsen (patinar) \n20. Nacht (noche) \n\n---\n\n### Historia 1: *Een Koud Nachtschaatsen* \n*Bij een donkere sneeuwnacht skate ik over het ijs van de meer. De maan schijnt zwak door de wolken, en de wind voelt ijzig op mijn wangen. Mijn hond, Pip, loopt naast me, zijn sporen in de schone sneeuw. Plotseling hoor ik een lachecho van een groepje vrienden die langs een boom groepen dansen, terwijl ze een boek over winteravonturen delen. "Laten we stoppen!" roept mijn vriend. Samen vieren we de stilte van de nacht, genietend van hete appels en heet thee...* \n\n**Traducción al español:** \n*En una noche oscura y nevada, patino sobre el hielo de un lago. La luna brilla débilmente entre las nubes, y el viento cortante goltea mis mejillas. Mi perro, Pip, camina a mi lado, dejando huellas en la nieve. De repente, escucho risas de un grupo de amigos junto a un árbol bailando en círculo, compartiendo un libro sobre aventuras invernales. ¡"Detengámonos!" grita un amigo. Celebramos el silencio de la noche con manzanas calientes y té caliente...* \n\n---\n\n### Historia 2: *Regen en Bloemen* \n*De regen kletterde op het dak, maar ik zat rustig in een rood stoel, lezend een boek met prachtige photo\'s van bloemen. Opeens hield de storm op, en er stak een zachte wind vanuit het noorden. Ik pakte mijn fiets enreed door een park vol pionussen en appelbomen. Toen ik een roze boom zag vol witte bloemen, stopte ik. Een kat zat onder de boom te slapen. \'Wat een schitterende dag!\' dacht ik. Het was alsof de wereld nieuw was geboren...* \n\n**Traducción al español:** \n*La lluvia golpeaba el techo, pero yo estaba tranquilo en una silla roja leyendo un libro con bellas fotos de flores. De pronto, la tormenta cesó y un suave viento soplando del norte. Tomé mi bicicleta y recorrí un parque lleno de nidos y manzanos. Al ver un árbol rosao con flores blancas, me detuve. Un gato dormía bajo él. "¡Qué hermoso día!" pensé. Como si el mundo se hubiera renacido...* \n\n---\n\n### Historia 3: *Vuurwerk Avond op het Kanaal* \n*Zaterdagavond, en de booten licht krioelden over het gracht. Muziek en lachen van een festival vulde de lucht. Toeristen dansten op een pier terwijl vuurwerk boven de zonsondergang ontplofte. Ik kocht visstokjes en vulde mijn boeket met bloemen van een straatveiling. Toen een zwarte kat vlak voor een vuurtoren kwam, glimlachte ik. "Wat een avond!" fluisterde ik terwijl de wind de geur van zout en papier rook.* \n\n**Traducción al español:** \n*Una noche sábado, los botes iluminados bullían por el canal. Música y risas de un festival llenaban el aire. Turistas bailaban en un muelle al ritmo de fuegos artificiales que estallaban sobre el atardecer. Compré brochetas de pescado y adquirí flores en un mercado callejero. Cuando un gato negro apareció cerca de un faro, sonreí. "¡Qué noche!" susurré, oliendo el viento a sal y papel...* \n\n--- \nLas historias incluyen todas las palabras en contexto, difieren en tema/estructura y se tradujeron con fidelidad.',
13]
14query_embeddings = model.encode_query(queries)
15document_embeddings = model.encode_document(documents)
16print(query_embeddings.shape, document_embeddings.shape)
17# [1, 768] [3, 768]
18
19# Get the similarity scores for the embeddings
20similarities = model.similarity(query_embeddings, document_embeddings)
21print(similarities)
22# tensor([[0.7780, 0.7080, 0.6299]])question and answer| question | answer | |
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Write a python function to calculate a baseball player's batting average given a list of hits and at-bats for each game in a season. The function should take a list of tuples as input, where each tuple contains two integers: the number of hits and the number of at-bats in a game. The function should return the player's overall batting average for the season as a float, rounded to three decimal places.[object Object][object Object]Input:[object Object]- A list of tuples, where each tuple contains two integers (hits, at-bats).[object Object][object Object]Output:[object Object]- A float, which is the player's batting average rounded to three decimal places.[object Object][object Object]Example:[object Object][object Object][object Object][object Object]Note: Batting average is calculated as the total number of hits divided by the total number of at-bats. | def calculate_batting_average(games):[object Object] total_hits = sum(hits for hits, at_bats in games)[object Object] total_at_bats = sum(at_bats for hits, at_bats in games)[object Object] if total_at_bats == 0:[object Object] return 0.0[object Object] batting_average = total_hits / total_at_bats[object Object] return round(batting_average, 3) |
A children's book author is designing a new storybook where each page contains a unique geometric illustration that is meant to enhance the visual appeal of the storyline. She plans to use a combination of regular polygons and fractal designs to achieve this.[object Object][object Object]1. She decides that each illustration will be centered around an inscribed regular hexagon within a circle. The hexagon's vertices are connected to form a series of nested equilateral triangles, where each subsequent triangle is half the side length of the previous one. If the circle has a radius of ( r ), find an expression for the total area covered by the infinite series of nested triangles. [object Object][object Object]2. The author also wants to incorporate a Sierpinski triangle in her design, with its largest triangle fitting perfectly within the regular hexagon. Given that the side length of the regular hexagon is ( s ), calculate the total area of the visible portion of the Sierpinski triangle after removing the first 5 iterations of inverted t... | To solve the problem, let's address each part separately.[object Object][object Object]### Part 1: Infinite Series of Nested Triangles[object Object][object Object]1. [object Object][object Object] - A regular hexagon inscribed in a circle of radius ( r ) has a side length ( s = r ).[object Object] - The area ( A ) of an equilateral triangle with side length ( s ) is given by:[object Object] [[object Object] A = \frac{\sqrt{3}}{4} s^2[object Object] ][object Object] - Here, ( s = r ), so the area of the largest triangle is:[object Object] [[object Object] A = \frac{\sqrt{3}}{4} r^2[object Object] ][object Object][object Object]2. [object Object][object Object] - The side length of each subsequent equilateral triangle is half the previous triangle's side length.[object Object] - Hence, the side length of the ( n )-th triangle is ( s_n = \frac{r}{2^{n-1}} ).[object Object] - The area of the ( n )-th triangle is:[object Object] [[object Object] A_n = \frac{\sqrt{3}}{4} \left(\frac{r}{2^{n-1}}\right)^2 = \frac{\sqrt{3}}{4} \cdot \frac{r^2}{4^{n-1}}[object Object] ][object Object][object Object]3. [object Object][object Object] - The total area ( T ) of the infinite... |
You are given an [object Object] with 10 vertices, labeled from [object Object] to [object Object]. The graph contains the following undirected edges. Each edge is represented as a tuple [object Object] ([object Object] is either 0 or 1), meaning an undirected edge [object Object]:[object Object](1, 8, 0)[object Object](8, 9, 0)[object Object](4, 8, 1)[object Object](0, 8, 1)[object Object](4, 7, 0)[object Object](1, 6, 1)[object Object](6, 8, 0)[object Object](6, 7, 1)[object Object](0, 9, 1)[object Object](3, 8, 0)[object Object](2, 6, 1)[object Object](5, 7, 0)[object Object](1, 4, 1)[object Object](6, 9, 1)[object Object](0, 7, 1)[object Object](3, 6, 1)[object Object](2, 4, 0)[object Object](0, 1, 1)[object Object](1, 9, 0)[object Object](4, 9, 0)[object Object](1, 2, 1)[object Object](0, 2, 0)[object Object](1, 5, 0)[object Object](0, 4, 1)[object Object](2, 7, 0)[object Object][object Object]Please select a subset of edges [object Object] such that:[object Object]- k = 9 (i.e., you select exactly 9 edges),[object Object]- The selected edges form a [object Object] — that is, they connect all 10 vertices without forming any cycles,[object Object]- There are exactly 6 edges with weight 1 in the selected edges,[object Object][object Object][object Object] Your final answer should be a single line containing the endpoints of the selected edges in order: `u_1 v_1 u_2 ... | [object Object]We need a spanning tree on 10 vertices (0–9) with 9 edges, exactly 6 of weight 1 and 3 of weight 0.[object Object][object Object]1. Notice the weight-0 subgraph is already connected, so an MST would take 9 zero-edges, but we must take only 3 zeros. [object Object]2. Strategy: use 6 weight-1 edges to form a tree on 7 vertices, then attach the 3 remaining vertices with 3 zero-edges. [object Object]3. Choose weight-1 edges among {0,1,2,4,6,7,9}:[object Object] (0,1), (1,2), (2,6), (6,7), (6,9), (1,4) – this is a tree on those 7 vertices. [object Object]4. Remaining vertices {3,5,8} are attached by zero-edges that connect into the tree:[object Object] (1,5), (8,9), (3,8). [object Object]5. Check: total edges = 6 (weight 1) + 3 (weight 0) = 9, all vertices connected, no cycles.[object Object][object Object]So the spanning tree edges are:[object Object]Weight 1: (0,1), (1,2), (2,6), (6,7), (6,9), (1,4) [object Object]Weight 0: (1,5), (8,9), (3,8)[object Object][object Object]Answer: 0 1 1 2 2 6 6 7 6 9 1 4 1 5 8 9 3 8 |
CachedMultipleNegativesRankingLoss with these parameters:
1{
2 "scale": 20.0,
3 "similarity_fct": "cos_sim",
4 "mini_batch_size": 32,
5 "gather_across_devices": false
6}question and answer| question | answer | |
|---|---|---|
| type | string | string |
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Please find the [object Object] that is greater than 9627104. | [object Object]We want the smallest palindrome > 9627104. Since this is a 7-digit number, any 7-digit palindrome has the form abc d cba.[object Object][object Object]1. Take the first four digits of 9627104, which are “9627” (that is a=9, b=6, c=2, d=7). [object Object]2. Mirror the first three digits (a,b,c = 9,6,2) onto the last three positions in reverse order: (c,b,a) = (2,6,9). [object Object]3. This gives the candidate palindrome 9627 269 → 9627269. [object Object]4. Compare with the original number: 9627269 > 9627104 (at the 5th digit 2>1), so it indeed exceeds the target. [object Object]5. Because we formed it by the minimal mirror of the leading half, it is the smallest such palindrome > 9627104.[object Object][object Object]Answer: 9627269 |
A die-hard Rio Ferdinand fan from Kenya is analyzing the performance statistics of his favorite football team. Rio Ferdinand, who played as a central defender, had a stellar career with a record of impressive defensive statistics. [object Object][object Object]1. Suppose Rio Ferdinand played 504 Premier League matches and the probability of him making a successful tackle in any given match is given by the probability mass function (P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!}), where (\lambda) is the average number of successful tackles per match. If it is known that (\lambda = 3), calculate the probability that Rio Ferdinand made exactly 5 successful tackles in a randomly selected match.[object Object][object Object]2. In addition, assume the fan wants to create a football trivia quiz. One of the questions is: "How many different ways can Rio Ferdinand's 504 Premier League matches be grouped into 4 distinct periods, such that each period contains at least one match?" Provide a mathematical expression to determine the number of ways t... | Let's solve the given math problem step-by-step:[object Object][object Object]### Part 1: Probability of Exactly 5 Successful Tackles[object Object][object Object]Given:[object Object]- ( \lambda = 3 )[object Object]- The probability mass function (PMF) for a Poisson distribution is:[object Object] [[object Object] P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!}[object Object] ][object Object]- We need to find ( P(X = 5) ).[object Object][object Object]Substitute ( \lambda = 3 ) and ( k = 5 ) into the PMF formula:[object Object][[object Object]P(X = 5) = \frac{e^{-3} \cdot 3^5}{5!}[object Object]][object Object][object Object]Calculate ( 3^5 ) and ( 5! ):[object Object][[object Object]3^5 = 243[object Object]][object Object][[object Object]5! = 5 \times 4 \times 3 \times 2 \times 1 = 120[object Object]][object Object][object Object]Substitute these values into the formula:[object Object][[object Object]P(X = 5) = \frac{e^{-3} \cdot 243}{120}[object Object]][object Object][object Object]Now, calculate ( e^{-3} ) (using ( e \approx 2.71828 )):[object Object][[object Object]e^{-3} \approx \frac{1}{e^3} \approx \frac{1}{20.0855} \approx 0.0498[object Object]][object Object][object Object]Substitute ( e^{-3} ) back into the formula:[object Object][[object Object]P(X = 5) = \frac{0.0498 \cdot 243}{120}[object Object]][object Object][object Object]Simplify the expression:[object Object][[object Object]P(X = 5) \approx \frac{12.1054}{120} \approx 0.1009[object Object]][object Object][object Object]### Part 2: Grouping Matches into 4 Distinct Periods[object Object][object Object]Given:[object Object]- Rio Ferdinand play... |
This is a logic puzzle. There are 5 houses (numbered 1 on the left, 5 on the right), from the perspective of someone standing across the street from them. Each has a different person in them. They have different characteristics:[object Object] - Each person has a unique name: [object Object], [object Object], [object Object], [object Object], [object Object][object Object] - People use different phone models: oneplus 9, google pixel 6, sony xperia 5, huawei p50, samsung galaxy s21[object Object] - Everyone has a favorite smoothie: [object Object], [object Object], [object Object], [object Object], [object Object][object Object] - The people keep different animals: [object Object], [object Object], [object Object], [object Object], [object Object][object Object] - Each mother is accompanied by their child: [object Object], [object Object], [object Object], [object Object], [object Object][object Object][object Object][object Object]## Clues:[object Object]1. The person who uses a OnePlus 9 is the person's child is named Alice.[object Object]2. Carol is the person's child is named Fred.[object Object]3. The person who uses a Huawei P50 is the Darkness smoothie drinker.[object Object]4. The Lemon smoothie lover is the person who is the mother of Timothy.[object Object]5. The bird keeper is David.[object Object]6. The person wh... | [object Object][object Object]The person living in House 1 is [object Object].[object Object][object Object][object Object][object Object][object Object]1. [object Object]: House 2 uses Google Pixel 6.[object Object]2. [object Object]: The sequence Horse-Fish-Bird must be consecutive. Placing them in Houses 2, 3, and 4 respectively:[object Object] - House 2: Horse (animal), Google Pixel 6 (phone).[object Object] - House 3: Fish (animal), Lemon smoothie (Clue 4), Samsung Galaxy S21 (Clue 14), child Timothy.[object Object] - House 4: David (Clue 5), Bird (animal).[object Object]3. [object Object]: The Lemon drinker (House 3) is the mother of Timothy and uses Samsung Galaxy S21.[object Object]4. [object Object]: Huawei P50 (Darkness smoothie) must be adjacent to Carol. Place Huawei in House 4 (David's house is Bird, so Carol must be in House 5 to be adjacent to House 4):[object Object] - House 5: Carol (child Fred via Clue 2), Huawei P50 (Darkness), and remaining phone Sony Xperia 5 in House 1 (Clue 10: Cat).[object Object]5. [object Object]: Sony Xperia 5 in House 1 has Cat as the animal.[object Object]6. [object Object]: OnePlus 9 must be in House 5 (Carol's house conflicts with child Fred). Adjust ... |
CachedMultipleNegativesRankingLoss with these parameters:
1{
2 "scale": 20.0,
3 "similarity_fct": "cos_sim",
4 "mini_batch_size": 32,
5 "gather_across_devices": false
6}1@inproceedings{reimers-2019-sentence-bert,
2 title = "Sentence-BERT: Sentence Embeddings using Siamese BERT-Networks",
3 author = "Reimers, Nils and Gurevych, Iryna",
4 booktitle = "Proceedings of the 2019 Conference on Empirical Methods in Natural Language Processing",
5 month = "11",
6 year = "2019",
7 publisher = "Association for Computational Linguistics",
8 url = "https://arxiv.org/abs/1908.10084",
9}1@misc{gao2021scaling,
2 title={Scaling Deep Contrastive Learning Batch Size under Memory Limited Setup},
3 author={Luyu Gao and Yunyi Zhang and Jiawei Han and Jamie Callan},
4 year={2021},
5 eprint={2101.06983},
6 archivePrefix={arXiv},
7 primaryClass={cs.LG}
8}