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| Metric | Value |
|---|---|
| Base Model | openai/gpt-oss-20b |
| Architecture | Mixture-of-Experts Transformer |
| Total Parameters | ~8.4B (pruned from 21B) |
| Original Experts per Layer | 32 |
| Pruned Experts per Layer | 11 |
| Layers | 24 |
| Top-k Routing | 4 |
| Context Length | 128K tokens |
| Attention Heads | 64 (Query), 8 (Key-Value) |
| Residual Dimension | 2880 |
| Attention Pattern | Alternating dense & sliding window (128 tokens) |
| Positional Encoding | RoPE (Rotary Position Embedding) |
| Normalization | RMSNorm |
| Precision | BF16 |
| License | Apache 2.0 |
| Specialization | Math |
1from transformers import AutoModelForCausalLM, AutoTokenizer
2import torch
3
4# Load the specialized model on CPU
5model = AutoModelForCausalLM.from_pretrained(
6 "AmanPriyanshu/gpt-oss-8.4b-specialized-math-pruned-moe-only-11-experts",
7 torch_dtype=torch.bfloat16,
8 device_map="cpu",
9 trust_remote_code=True
10)
11tokenizer = AutoTokenizer.from_pretrained("AmanPriyanshu/gpt-oss-8.4b-specialized-math-pruned-moe-only-11-experts")
12
13# Generate with the model
14messages = [
15 {"role": "user", "content": "Solve this equation: 2x + 5 = 17. Show your work step by step."}
16]
17
18inputs = tokenizer.apply_chat_template(
19 messages,
20 add_generation_prompt=True,
21 return_tensors="pt",
22 return_dict=True,
23 reasoning_effort="medium"
24)
25
26# Ensure inputs are on the same device as model
27inputs = {k: v.to(model.device) for k, v in inputs.items()}
28
29outputs = model.generate(
30 **inputs,
31 max_new_tokens=512,
32 do_sample=True,
33 temperature=0.1,
34 top_p=0.9,
35 pad_token_id=tokenizer.eos_token_id,
36 eos_token_id=tokenizer.eos_token_id
37)
38
39# Decode only the generated part
40input_length = inputs['input_ids'].shape[1]
41response_tokens = outputs[0][input_length:]
42response = tokenizer.decode(response_tokens, skip_special_tokens=True)
43print(response)1from transformers import AutoModelForCausalLM, AutoTokenizer
2import torch
3
4# Check MPS availability and load model
5device = "mps" if torch.backends.mps.is_available() else "cpu"
6
7model = AutoModelForCausalLM.from_pretrained(
8 "AmanPriyanshu/gpt-oss-8.4b-specialized-math-pruned-moe-only-11-experts",
9 torch_dtype=torch.float16, # Better MPS compatibility
10 device_map=device,
11 trust_remote_code=True,
12 low_cpu_mem_usage=True
13)
14tokenizer = AutoTokenizer.from_pretrained("AmanPriyanshu/gpt-oss-8.4b-specialized-math-pruned-moe-only-11-experts")
15
16# Generate with the model
17messages = [
18 {"role": "user", "content": "Solve this equation: 2x + 5 = 17. Show your work step by step."}
19]
20
21inputs = tokenizer.apply_chat_template(
22 messages,
23 add_generation_prompt=True,
24 return_tensors="pt",
25 return_dict=True,
26 reasoning_effort="medium"
27)
28
29# Move inputs to model device
30inputs = {k: v.to(model.device) if isinstance(v, torch.Tensor) else v for k, v in inputs.items()}
31
32# Use torch.no_grad for MPS stability
33with torch.no_grad():
34 outputs = model.generate(
35 **inputs,
36 max_new_tokens=512,
37 do_sample=True,
38 temperature=0.1,
39 top_p=0.9,
40 pad_token_id=tokenizer.eos_token_id,
41 eos_token_id=tokenizer.eos_token_id,
42 use_cache=True
43 )
44
45# Decode only the generated part
46input_length = inputs['input_ids'].shape[1]
47response_tokens = outputs[0][input_length:]
48response = tokenizer.decode(response_tokens, skip_special_tokens=True)
49print(response)1device_map="auto" # Will automatically use GPU if available
2torch_dtype=torch.bfloat16 # or torch.float16<|channel|>analysis<|message|>We need to solve 2x+5=17. Steps: subtract 5, divide by 2. Provide explanation.<|end|><|start|>assistant<|channel|>final<|message|>**Equation to solve**
\[
2x + 5 = 17
\]
---
### Step 1: Isolate the term containing the variable
Subtract the constant term from both sides of the equation.
\[
2x + 5 - 5 = 17 - 5
\]
\[
2x = 12
\]
---
### Step 2: Solve for \(x\)
Divide both sides by the coefficient of \(x\) (which is 2).
\[
\frac{2x}{2} = \frac{12}{2}
\]
\[
x = 6
\]
---
### Result
\[
\boxed{x = 6}
\]
**Check**:
\(2(6) + 5 = 12 + 5 = 17\), which matches the original equation.<|return|><|channel|>analysis<|message|>Need explain theorem, usage.<|end|><|start|>assistant<|channel|>final<|message|>**Pyth‑theorem**
- **Statement**: In a triangle with sides *a*, *b*, *c* (where *c* is the longest side, the “hyp‑side”), the square of the longest side equals the sum of the squares of the other two sides.
\[
a^{2}+b^{2}=c^{2}
\]
- **Why**: It follows from the geometry of a triangle (area, angles) or from the algebraic definition of a distance in a 2‑dimensional space (the “Euclidean distance” in a vector space).
---
## How it is used
| **Field** | **Application** | **Key idea** |
|---|---|---|
| **Geometry** | Finding the lengths of a triangle (given two sides, find the third). | Rearsolve \(c=\sqrt{a^{2}+b^{2}}\). |
| **Engineering** | Calculing the height of a bridge, the width of a wall, or the length of a cable. | Use the formula to find the required dimensions. |
| **Computer graphics** | Determing the distance between two points in a 2‑D space. | Distance \(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\). |
| **Physics** | In a 2‑D or 3‑D system, the conservation of energy or momentum (e.g., \(E=mc^{2}\)). | The “energy” is proportional to the square of the distance. |
| **Mat‑analysis** | Pro proving that the triangle inequality holds, or proving that the “Euclidean norm” is a metric. | Use the Pyth‑theorem as a basis for the metric’s properties. |
---
### Quick example
Supp you have a triangle with sides 3 cm and 4 cm.
Find the longest side:
\[
c=\sqrt{3^{2}+4^{2}}=\sqrt{9+16}=\sqrt{25}=5\text{ cm}
\]
So the triangle is 3‑4‑5, a classic “Pyth‑theorem” triangle.
---
**Bottom line**: The Pyth‑theorem is the “law of the squares” for a triangle (or a 2‑D space). It is used whenever<|channel|>analysis<|message|>Need area = π r^2. r=7 => 49π. Provide numeric.<|end|><|start|>assistant<|channel|>final<|message|>The area of a circle is given by the formula
\[
A = \pi r^{2}
\]
where \(r\) is the radius.
For a radius of \(7\) meters:
\[
A = \pi (7\,\text{m})^{2}
= \pi \times 49\,\text{m}^{2}
= 49\pi \,\text{m}^{2}
\]
So the area is **\(49\pi\) square meters**, which is approximately:
\[
49\pi \approx 49 \times 3.14159 \approx 154.16 \text{ m}^{2}
\]<|return|>1@misc{priyanshu2025gptoss,
2 title={{GPT-OSS MoE Expert Fingerprinting: Analyzing Expert Activation Patterns in Mixture of Experts Models}},
3 author={Priyanshu, Aman and Vijay, Supriti},
4 year={2025},
5 howpublished={\url{https://amanpriyanshu.github.io/GPT-OSS-MoE-ExpertFingerprinting/}},
6 note={Interactive analysis tool for expert activation patterns in MoE architectures}
7}