Views
No views yet
| Metric | Value |
|---|---|
| Base Model | openai/gpt-oss-20b |
| Architecture | Mixture-of-Experts Transformer |
| Total Parameters | ~20.3B (pruned from 21B) |
| Original Experts per Layer | 32 |
| Pruned Experts per Layer | 31 |
| Layers | 24 |
| Top-k Routing | 4 |
| Context Length | 128K tokens |
| Attention Heads | 64 (Query), 8 (Key-Value) |
| Residual Dimension | 2880 |
| Attention Pattern | Alternating dense & sliding window (128 tokens) |
| Positional Encoding | RoPE (Rotary Position Embedding) |
| Normalization | RMSNorm |
| Precision | BF16 |
| License | Apache 2.0 |
| Specialization | Math |
1from transformers import AutoModelForCausalLM, AutoTokenizer
2import torch
3
4# Load the specialized model on CPU
5model = AutoModelForCausalLM.from_pretrained(
6 "AmanPriyanshu/gpt-oss-20.3b-specialized-math-pruned-moe-only-31-experts",
7 torch_dtype=torch.bfloat16,
8 device_map="cpu",
9 trust_remote_code=True
10)
11tokenizer = AutoTokenizer.from_pretrained("AmanPriyanshu/gpt-oss-20.3b-specialized-math-pruned-moe-only-31-experts")
12
13# Generate with the model
14messages = [
15 {"role": "user", "content": "Solve this equation: 2x + 5 = 17. Show your work step by step."}
16]
17
18inputs = tokenizer.apply_chat_template(
19 messages,
20 add_generation_prompt=True,
21 return_tensors="pt",
22 return_dict=True,
23 reasoning_effort="medium"
24)
25
26# Ensure inputs are on the same device as model
27inputs = {k: v.to(model.device) for k, v in inputs.items()}
28
29outputs = model.generate(
30 **inputs,
31 max_new_tokens=512,
32 do_sample=True,
33 temperature=0.1,
34 top_p=0.9,
35 pad_token_id=tokenizer.eos_token_id,
36 eos_token_id=tokenizer.eos_token_id
37)
38
39# Decode only the generated part
40input_length = inputs['input_ids'].shape[1]
41response_tokens = outputs[0][input_length:]
42response = tokenizer.decode(response_tokens, skip_special_tokens=True)
43print(response)1from transformers import AutoModelForCausalLM, AutoTokenizer
2import torch
3
4# Check MPS availability and load model
5device = "mps" if torch.backends.mps.is_available() else "cpu"
6
7model = AutoModelForCausalLM.from_pretrained(
8 "AmanPriyanshu/gpt-oss-20.3b-specialized-math-pruned-moe-only-31-experts",
9 torch_dtype=torch.float16, # Better MPS compatibility
10 device_map=device,
11 trust_remote_code=True,
12 low_cpu_mem_usage=True
13)
14tokenizer = AutoTokenizer.from_pretrained("AmanPriyanshu/gpt-oss-20.3b-specialized-math-pruned-moe-only-31-experts")
15
16# Generate with the model
17messages = [
18 {"role": "user", "content": "Solve this equation: 2x + 5 = 17. Show your work step by step."}
19]
20
21inputs = tokenizer.apply_chat_template(
22 messages,
23 add_generation_prompt=True,
24 return_tensors="pt",
25 return_dict=True,
26 reasoning_effort="medium"
27)
28
29# Move inputs to model device
30inputs = {k: v.to(model.device) if isinstance(v, torch.Tensor) else v for k, v in inputs.items()}
31
32# Use torch.no_grad for MPS stability
33with torch.no_grad():
34 outputs = model.generate(
35 **inputs,
36 max_new_tokens=512,
37 do_sample=True,
38 temperature=0.1,
39 top_p=0.9,
40 pad_token_id=tokenizer.eos_token_id,
41 eos_token_id=tokenizer.eos_token_id,
42 use_cache=True
43 )
44
45# Decode only the generated part
46input_length = inputs['input_ids'].shape[1]
47response_tokens = outputs[0][input_length:]
48response = tokenizer.decode(response_tokens, skip_special_tokens=True)
49print(response)1device_map="auto" # Will automatically use GPU if available
2torch_dtype=torch.bfloat16 # or torch.float16<|channel|>analysis<|message|>Just solve linear equation.<|end|><|start|>assistant<|channel|>final<|message|>**Equation to solve**
\[
2x + 5 = 17
\]
---
### Step 1: Isolate the term with \(x\)
Subtract \(5\) from both sides of the equation to get the variable term alone on the left:
\[
\begin{aligned}
2x + 5 - 5 &= 17 - 5 \\
2x &= 12
\end{aligned}
\]
---
### Step 2: Solve for \(x\)
Divide both sides by the coefficient of \(x\), which is \(2\):
\[
\begin{aligned}
\frac{2x}{2} &= \frac{12}{2} \\
x &= 6
\end{aligned}
\]
---
### Step 3: Verify the solution
Plug \(x = 6\) back into the original equation:
\[
2(6) + 5 = 12 + 5 = 17
\]
The left‑hand side equals the right‑hand side, so the solution is correct.
---
\[
\boxed{x = 6}
\]<|return|><|channel|>analysis<|message|>Need explain theorem and usage.<|end|><|start|>assistant<|channel|>final<|message|>**Pythagorean Theorem**
> In a right‑angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) equals the sum of the squares of the lengths of the other two sides.
Mathematically:
\[
c^{2}=a^{2}+b^{2}
\]
where
- \(c\) = length of the hypotenuse,
- \(a\) and \(b\) = lengths of the two legs.
---
### How It’s Used
| Context | What you do | Example |
|---------|-------------|---------|
| **Finding a missing side** | Rearrange the formula to solve for the unknown side. | Triangle with legs 3 m and 4 m → \(c=\sqrt{3^{2}+4^{2}}=\sqrt{9+16}=5\) m. |
| **Checking if a triangle is right‑angled** | Verify if \(c^{2}=a^{2}+b^{2}\). | Triangle sides 5, 12, 13 → \(5^{2}+12^{2}=25+144=169=13^{2}\). |
| **Distance between two points** | Treat the coordinate differences as legs. | Points (2, 3) and (5, 11): Δx=3, Δy=8 → distance \(=\sqrt{3^{2}+8^{2}}=\sqrt{9+64}=√73\). |
| **Engineering & construction** | Design right‑angled structures, calculate beam lengths, etc. | Determining the length of a diagonal support in a rectangular frame. |
| **Computer graphics** | Compute pixel distances, collision detection, etc. | Finding the Euclidean distance between two vertices in a 2‑D or 3‑D space. |
| **Navigation & GPS** | Approximate straight‑line distances over small areas. | Estimating the shortest path between two geographic coordinates. |
| **Physics** | Resolve vectors into perpendicular components. | Decomposing a force into horizontal and vertical components. |
---
### Quick Tips
- **Always label the hypotenuse** as the side opposite the right angle; it’s the longest side.
- For **non‑right triangles**, use the Law of Cosines: \(c^{2}=a^{2}+b^{2}-2ab\cos<|channel|>analysis<|message|>Need area πr^2 = π*49 = 49π ≈ 153.938.<|end|><|start|>assistant<|channel|>final<|message|>The area \(A\) of a circle is given by
\[
A = \pi r^{2}
\]
where \(r\) is the radius.
For a radius of \(7\) m:
\[
A = \pi (7\,\text{m})^{2}
= \pi \times 49\,\text{m}^2
= 49\pi \,\text{m}^2
\]
If you want a numerical value using \(\pi \approx 3.14159\):
\[
A \approx 49 \times 3.14159 \approx 153.938 \,\text{m}^2
\]
So the area is **\(49\pi\) square meters** (about **153.94 m²**).<|return|>1@misc{priyanshu2025gptoss,
2 title={{GPT-OSS MoE Expert Fingerprinting: Analyzing Expert Activation Patterns in Mixture of Experts Models}},
3 author={Priyanshu, Aman and Vijay, Supriti},
4 year={2025},
5 howpublished={\url{https://amanpriyanshu.github.io/GPT-OSS-MoE-ExpertFingerprinting/}},
6 note={Interactive analysis tool for expert activation patterns in MoE architectures}
7}