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| Metric | Value |
|---|---|
| Base Model | openai/gpt-oss-20b |
| Architecture | Mixture-of-Experts Transformer |
| Total Parameters | ~13.7B (pruned from 21B) |
| Original Experts per Layer | 32 |
| Pruned Experts per Layer | 20 |
| Layers | 24 |
| Top-k Routing | 4 |
| Context Length | 128K tokens |
| Attention Heads | 64 (Query), 8 (Key-Value) |
| Residual Dimension | 2880 |
| Attention Pattern | Alternating dense & sliding window (128 tokens) |
| Positional Encoding | RoPE (Rotary Position Embedding) |
| Normalization | RMSNorm |
| Precision | BF16 |
| License | Apache 2.0 |
| Specialization | Math |
1from transformers import AutoModelForCausalLM, AutoTokenizer
2import torch
3
4# Load the specialized model on CPU
5model = AutoModelForCausalLM.from_pretrained(
6 "AmanPriyanshu/gpt-oss-13.7b-specialized-math-pruned-moe-only-20-experts",
7 torch_dtype=torch.bfloat16,
8 device_map="cpu",
9 trust_remote_code=True
10)
11tokenizer = AutoTokenizer.from_pretrained("AmanPriyanshu/gpt-oss-13.7b-specialized-math-pruned-moe-only-20-experts")
12
13# Generate with the model
14messages = [
15 {"role": "user", "content": "Solve this equation: 2x + 5 = 17. Show your work step by step."}
16]
17
18inputs = tokenizer.apply_chat_template(
19 messages,
20 add_generation_prompt=True,
21 return_tensors="pt",
22 return_dict=True,
23 reasoning_effort="medium"
24)
25
26# Ensure inputs are on the same device as model
27inputs = {k: v.to(model.device) for k, v in inputs.items()}
28
29outputs = model.generate(
30 **inputs,
31 max_new_tokens=512,
32 do_sample=True,
33 temperature=0.1,
34 top_p=0.9,
35 pad_token_id=tokenizer.eos_token_id,
36 eos_token_id=tokenizer.eos_token_id
37)
38
39# Decode only the generated part
40input_length = inputs['input_ids'].shape[1]
41response_tokens = outputs[0][input_length:]
42response = tokenizer.decode(response_tokens, skip_special_tokens=True)
43print(response)1from transformers import AutoModelForCausalLM, AutoTokenizer
2import torch
3
4# Check MPS availability and load model
5device = "mps" if torch.backends.mps.is_available() else "cpu"
6
7model = AutoModelForCausalLM.from_pretrained(
8 "AmanPriyanshu/gpt-oss-13.7b-specialized-math-pruned-moe-only-20-experts",
9 torch_dtype=torch.float16, # Better MPS compatibility
10 device_map=device,
11 trust_remote_code=True,
12 low_cpu_mem_usage=True
13)
14tokenizer = AutoTokenizer.from_pretrained("AmanPriyanshu/gpt-oss-13.7b-specialized-math-pruned-moe-only-20-experts")
15
16# Generate with the model
17messages = [
18 {"role": "user", "content": "Solve this equation: 2x + 5 = 17. Show your work step by step."}
19]
20
21inputs = tokenizer.apply_chat_template(
22 messages,
23 add_generation_prompt=True,
24 return_tensors="pt",
25 return_dict=True,
26 reasoning_effort="medium"
27)
28
29# Move inputs to model device
30inputs = {k: v.to(model.device) if isinstance(v, torch.Tensor) else v for k, v in inputs.items()}
31
32# Use torch.no_grad for MPS stability
33with torch.no_grad():
34 outputs = model.generate(
35 **inputs,
36 max_new_tokens=512,
37 do_sample=True,
38 temperature=0.1,
39 top_p=0.9,
40 pad_token_id=tokenizer.eos_token_id,
41 eos_token_id=tokenizer.eos_token_id,
42 use_cache=True
43 )
44
45# Decode only the generated part
46input_length = inputs['input_ids'].shape[1]
47response_tokens = outputs[0][input_length:]
48response = tokenizer.decode(response_tokens, skip_special_tokens=True)
49print(response)1device_map="auto" # Will automatically use GPU if available
2torch_dtype=torch.bfloat16 # or torch.float16<|channel|>analysis<|message|>We need to solve 2x+5=17. Subtract 5: 2x=12. Divide 2: x=6. Provide step-by-step.<|end|><|start|>assistant<|channel|>final<|message|>**Step 1 – Write the equation**
\[
2x + 5 = 17
\]
**Step 2 – Isolate the term with \(x\)**
Subtract 5 from both sides so that the constant term disappears:
\[
2x + 5 - 5 = 17 - 5
\]
\[
2x = 12
\]
**Step 3 – Solve for \(x\)**
Divide both sides by 2 (the coefficient of \(x\)):
\[
\frac{2x}{2} = \frac{12}{2}
\]
\[
x = 6
\]
---
**Answer:** \(x = 6\)
(You can check by plugging back: \(2(6)+5 = 12+5 = 17\), which matches the right‑hand side.)<|return|><|channel|>analysis<|message|>Need explain theorem, formula, usage.<|end|><|start|>assistant<|channel|>final<|message|>**The Pythagorean Theorem**
> In a right‑angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) equals the sum of the squares of the lengths of the other two sides.
Mathematically:
\[
a^{2} + b^{2} = c^{2}
\]
where
* \(a\) and \(b\) are the legs (the two sides that form the right angle),
* \(c\) is the hypotenuse.
---
### How It Is Used
| Application | What you do | Example |
|-------------|-------------|---------|
| **Finding a missing side** | Rear‑solve the equation for the unknown side | In a triangle with legs 3 m and 4 m, \(c = \sqrt{3^{2}+4^{2}} = 5\) m. |
| **Checking if a triangle is right‑angled** | Verify if \(a^{2}+b^{2}=c^{2}\) | For sides 6, 8, 10: \(6^{2}+8^{2}=36+64=100=10^{2}\) → right triangle. |
| **Design & construction** | Ensure structural elements meet right‑angle requirements (e.g., building corners, ladders). | A carpenter uses the theorem to calculate the length of a diagonal brace. |
| **Navigation & surveying** | Compute distances when only horizontal and vertical components are known. | A hiker measures 200 m east and 150 m north; the straight‑away distance is \(\sqrt{200^{2}+150^{2}}\). |
| **Computer graphics & animation** | Determine pixel distances, collision detection, or rendering of right‑angled shapes. | A program calculates the distance between two points in a 2‑D grid. |
| **Physics & engineering** | Resolve forces, velocities, or displacements into perpendicular components. | A projectile’s horizontal and vertical speeds combine to give the resultant speed. |
| **Mathematics & education** | Introduce geometry, algebra, and proof techniques. | Students prove that the area of a square built on each side of a right triangle satisfies the theorem. |
---
### Quick “Rule of Thumb”
- **If you know two sides** → compute the third with \(c = \sqrt{a^{<|channel|>analysis<|message|>Need area πr^2 = π*49 ≈ 153.938.<|end|><|start|>assistant<|channel|>final<|message|>The area \(A\) of a circle is given by
\[
A = \pi r^{2}
\]
where \(r\) is the radius.
For \(r = 7\) m:
\[
A = \pi (7\ \text{m})^{2}
= \pi \times 49\ \text{m}^{2}
\approx 3.14159 \times 49\ \text{m}^{2}
\approx 153.938\ \text{m}^{2}
\]
So the circle has an area of about **\(154\ \text{m}^{2}\)** (rounded to the nearest square meter).<|return|>1@misc{priyanshu2025gptoss,
2 title={{GPT-OSS MoE Expert Fingerprinting: Analyzing Expert Activation Patterns in Mixture of Experts Models}},
3 author={Priyanshu, Aman and Vijay, Supriti},
4 year={2025},
5 howpublished={\url{https://amanpriyanshu.github.io/GPT-OSS-MoE-ExpertFingerprinting/}},
6 note={Interactive analysis tool for expert activation patterns in MoE architectures}
7}