Tables:
CREATE TABLE employees (
    EMPLOYEE_ID decimal(6,0),
    FIRST_NAME varchar(20),
    LAST_NAME varchar(25),
    EMAIL varchar(25),
    PHONE_NUMBER varchar(20),
    HIRE_DATE date,
    JOB_ID varchar(10),
    SALARY decimal(8,2),
    COMMISSION_PCT decimal(2,2),
    MANAGER_ID decimal(6,0),
    DEPARTMENT_ID decimal(4,0)
)

CREATE TABLE jobs (
    JOB_ID varchar(10),
    JOB_TITLE varchar(35),
    MIN_SALARY decimal(6,0),
    MAX_SALARY decimal(6,0)
)

CREATE TABLE locations (
    LOCATION_ID decimal(4,0),
    STREET_ADDRESS varchar(40),
    POSTAL_CODE varchar(12),
    CITY varchar(30),
    STATE_PROVINCE varchar(25),
    COUNTRY_ID varchar(2)
)

CREATE TABLE countries (
    COUNTRY_ID varchar(2),
    COUNTRY_NAME varchar(40),
    REGION_ID decimal(10,0)
)

CREATE TABLE job_history (
    EMPLOYEE_ID decimal(6,0),
    START_DATE date,
    END_DATE date,
    JOB_ID varchar(10),
    DEPARTMENT_ID decimal(4,0)
)

CREATE TABLE regions (
    REGION_ID decimal(5,0),
    REGION_NAME varchar(25)
)

CREATE TABLE departments (
    DEPARTMENT_ID decimal(4,0),
    DEPARTMENT_NAME varchar(30),
    MANAGER_ID decimal(6,0),
    LOCATION_ID decimal(4,0)
)

Question:
For those employees who did not have any job in the past, give me the comparison about the amount of job_id over the job_id , and group by attribute job_id, and list from low to high by the JOB_ID please.

Answer:

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BASELINE ANSWER:
SELECT JOB_ID, COUNT(JOB_ID) FROM employees WHERE NOT EMPLOYEE_ID IN (SELECT EMPLOYEE_ID FROM job_history) GROUP BY JOB_ID ORDER BY JOB_ID

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MODEL RESPONSE:
SELECT JOB_ID, COUNT(JOB_ID) FROM employees WHERE NOT EMPLOYEE_ID IN (SELECT EMPLOYEE_ID FROM job_history) ORDER BY JOB_ID DESC