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| Metric | Value |
|---|---|
| Base Model | openai/gpt-oss-20b |
| Architecture | Mixture-of-Experts Transformer |
| Total Parameters | ~12.0B (pruned from 21B) |
| Original Experts per Layer | 32 |
| Pruned Experts per Layer | 17 |
| Layers | 24 |
| Top-k Routing | 4 |
| Context Length | 128K tokens |
| Attention Heads | 64 (Query), 8 (Key-Value) |
| Residual Dimension | 2880 |
| Attention Pattern | Alternating dense & sliding window (128 tokens) |
| Positional Encoding | RoPE (Rotary Position Embedding) |
| Normalization | RMSNorm |
| Precision | BF16 |
| License | Apache 2.0 |
| Specialization | Math |
1from transformers import AutoModelForCausalLM, AutoTokenizer
2import torch
3
4# Load the specialized model on CPU
5model = AutoModelForCausalLM.from_pretrained(
6 "AmanPriyanshu/gpt-oss-12.0b-specialized-math-pruned-moe-only-17-experts",
7 torch_dtype=torch.bfloat16,
8 device_map="cpu",
9 trust_remote_code=True
10)
11tokenizer = AutoTokenizer.from_pretrained("AmanPriyanshu/gpt-oss-12.0b-specialized-math-pruned-moe-only-17-experts")
12
13# Generate with the model
14messages = [
15 {"role": "user", "content": "Solve this equation: 2x + 5 = 17. Show your work step by step."}
16]
17
18inputs = tokenizer.apply_chat_template(
19 messages,
20 add_generation_prompt=True,
21 return_tensors="pt",
22 return_dict=True,
23 reasoning_effort="medium"
24)
25
26# Ensure inputs are on the same device as model
27inputs = {k: v.to(model.device) for k, v in inputs.items()}
28
29outputs = model.generate(
30 **inputs,
31 max_new_tokens=512,
32 do_sample=True,
33 temperature=0.1,
34 top_p=0.9,
35 pad_token_id=tokenizer.eos_token_id,
36 eos_token_id=tokenizer.eos_token_id
37)
38
39# Decode only the generated part
40input_length = inputs['input_ids'].shape[1]
41response_tokens = outputs[0][input_length:]
42response = tokenizer.decode(response_tokens, skip_special_tokens=True)
43print(response)1from transformers import AutoModelForCausalLM, AutoTokenizer
2import torch
3
4# Check MPS availability and load model
5device = "mps" if torch.backends.mps.is_available() else "cpu"
6
7model = AutoModelForCausalLM.from_pretrained(
8 "AmanPriyanshu/gpt-oss-12.0b-specialized-math-pruned-moe-only-17-experts",
9 torch_dtype=torch.float16, # Better MPS compatibility
10 device_map=device,
11 trust_remote_code=True,
12 low_cpu_mem_usage=True
13)
14tokenizer = AutoTokenizer.from_pretrained("AmanPriyanshu/gpt-oss-12.0b-specialized-math-pruned-moe-only-17-experts")
15
16# Generate with the model
17messages = [
18 {"role": "user", "content": "Solve this equation: 2x + 5 = 17. Show your work step by step."}
19]
20
21inputs = tokenizer.apply_chat_template(
22 messages,
23 add_generation_prompt=True,
24 return_tensors="pt",
25 return_dict=True,
26 reasoning_effort="medium"
27)
28
29# Move inputs to model device
30inputs = {k: v.to(model.device) if isinstance(v, torch.Tensor) else v for k, v in inputs.items()}
31
32# Use torch.no_grad for MPS stability
33with torch.no_grad():
34 outputs = model.generate(
35 **inputs,
36 max_new_tokens=512,
37 do_sample=True,
38 temperature=0.1,
39 top_p=0.9,
40 pad_token_id=tokenizer.eos_token_id,
41 eos_token_id=tokenizer.eos_token_id,
42 use_cache=True
43 )
44
45# Decode only the generated part
46input_length = inputs['input_ids'].shape[1]
47response_tokens = outputs[0][input_length:]
48response = tokenizer.decode(response_tokens, skip_special_tokens=True)
49print(response)1device_map="auto" # Will automatically use GPU if available
2torch_dtype=torch.bfloat16 # or torch.float16<|channel|>analysis<|message|>We need to solve 2x+5=17. Steps: subtract 5, divide by 2. Provide explanation.<|end|><|start|>assistant<|channel|>final<|message|>**Equation to solve**
\[
2x + 5 = 17
\]
---
### Step 1: Isolate the term with the variable
Subtract 5 from both sides so that the variable term is alone on the left side.
\[
2x + 5 - 5 = 17 - 5
\]
\[
2x = 12
\]
---
### Step 2: Solve for \(x\)
Divide both sides by 2 (the coefficient of \(x\)).
\[
\frac{2x}{2} = \frac{12}{2}
\]
\[
x = 6
\]
---
### Check (optional)
Plug \(x = 6\) back into the original equation:
\[
2(6) + 5 = 12 + 5 = 17
\]
The left side equals the right side, so the solution is correct.
---
\[
\boxed{x = 6}
\]<|return|><|channel|>analysis<|message|>Need explain theorem, formula, usage.<|end|><|start|>assistant<|channel|>final<|message|>## The Pythagorean Theorem
**Statement**
> In a right‑angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) equals the sum of the squares of the lengths of the other two sides.
Mathematically:
\[
c^{2}=a^{2}+b^{2}
\]
where
- \(a\) and \(b\) are the lengths of the legs (the two sides that form the right angle),
- \(c\) is the length of the hypotenuse.
---
## How It Is Used
| **Purpose** | **Typical Application** | **Example** |
|-------------|------------------------|-------------|
| **Finding a missing side** | Compute a side when the other two are known | Triangle with legs 3 m and 4 m → \(c=\sqrt{3^{2}+4^{2}}=\sqrt{25}=5\) m |
| **Verifying a triangle is right‑angled** | Check if \(a^{2}+b^{2}=c^{2}\) | Triangle with sides 5, 12, 13 → \(5^{2}+12^{2}=25+144=169=13^{2}\) |
| **Geometry & Engineering** | Design of shapes, structural calculations, CAD modeling | Determining the height of a roof slangle from base width and slope |
| **Computer Graphics & Animation** | Calculating distances, normals, and angles in 3‑D space | Rendering a right‑angled corner in a 3‑D scene |
| **Physics & Kinematics** | Solving for unknowns in right‑triangle motion problems | Finding the distance a projectile travels given horizontal and vertical components |
| **Mathematics & Algebra** | Solving quadratic equations, proving identities | Deriving the formula for the area of a right‑triangle: \(A=\frac{1}{2}ab\) |
| **Education & Learning** | Teaching geometry, problem‑solving, spatial reasoning | Pythagorean puzzles, “find the missing side” games |
---
## Quick Steps to Apply
1. **Identify the right angle** (or confirm that the triangle is right‑angled).
2. **Label the sides**: \(a\), \(b\) (legs), \(c\) (hypotenuse).
3<|channel|>analysis<|message|>Need area = π r^2 = π*49 ≈ 153.938.<|end|><|start|>assistant<|channel|>final<|message|>The area \(A\) of a circle is given by
\[
A = \pi r^{2}
\]
where \(r\) is the radius.
For \(r = 7\ \text{m}\):
\[
A = \pi (7\ \text{m})^{2}
= \pi \times 49\ \text{m}^{2}
\approx 3.14159 \times 49\ \text{m}^{2}
\approx 153.938\ \text{m}^{2}
\]
So the area of the circle is **about \(154\ \text{m}^{2}\)** (rounded to the nearest whole number).<|return|>1@misc{priyanshu2025gptoss,
2 title={{GPT-OSS MoE Expert Fingerprinting: Analyzing Expert Activation Patterns in Mixture of Experts Models}},
3 author={Priyanshu, Aman and Vijay, Supriti},
4 year={2025},
5 howpublished={\url{https://amanpriyanshu.github.io/GPT-OSS-MoE-ExpertFingerprinting/}},
6 note={Interactive analysis tool for expert activation patterns in MoE architectures}
7}